Question

If the circular orbit of a synchronous satellite is 6r above the Earth's radius r, the radius of the Earth will be the orbit of another artificial satellite at 2.5r above the Earth's surface.

Answer 1

Answer:

For geostationary satellite :        r1=R+6R=7R            T1=24 h

For second satellite :     r2=R+2.5R=3.5R            

Time period of satellite :       T=2πGMr3          where,  r is the radius of orbit

⟹    T1T2=r13r23

∴       24T2=(7R)3(3.5R)3=221

⟹   T2=2224=62 h