If the circumcentre of the triangle with
vertices (a, -1), (6, -9) and (10, b) is (6,-5),
find the values of a and b.
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Let, (x, y) be the coordinates of the circumcenter.
D1 be the distance from the circumcenter to vertex A
D2 be the distance from the circumcenter to vertex B
D3 be the distance from the circumcenter to vertex C
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Let x1,x2 and x3 be a,6,10 respectively.
Let y1,y2 and y3 be -1,-9,b respectively.
For x = x1+x2+x3/3
6 = a+6+10/3
6 × 3 = 16+a
18 = 16+a
18-16 = a
a = 2
For y = y1+y2+y3/3
-5 = (-1)+(-9)+b/3
-5 = -1-9+b/3
-5×3 = -10+b
-15 = -10+b
-15+10 = b
b= -5
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