Question

if the circumference of a circle is 22 centimetre find its diameter​

Answer 1

Answer :-

• The diameter of the circle is 7cm.

Step-by-step explanation:

To Find :-

• The diameter of circle

Solution:

Given that,

• The circumference of circle = 22cm

We know that,

$\bigstar \: \boxed{\bf{Circumference \: of \: circle = 2 \: \pi \: r}}$

∴ The radius of circle :-

$\bf{\longmapsto \: 2 \: \pi \: r = circumference} \\ \\ \\ \\ \bf{\longmapsto \: 2 \times \: \dfrac{22}{7} \times \: r = 22} \\ \\ \\ \\ \bf{\longmapsto \: \dfrac{2 \times 22}{7} \times \: r = 22} \\ \\ \\ \\ \bf{\longmapsto \: \dfrac{44}{7} \times \: r = 22} \\ \\ \\ \\ \bf{\longmapsto \: r = 22 \times \dfrac{7}{44}} \\ \\ \\ \\ \bf{\longmapsto \: r = \dfrac{22 \times 7}{44}} \\ \\ \\ \\ \bf{\longmapsto \: r = \dfrac{154}{44}} \\ \\ \\ \\ \bf{\longmapsto \: r = \cancel{\dfrac{154}{44}}} \\ \\ \\ \\ \bf{\longmapsto \: \orange{r = 3.5}}$

Hence, The radius of circle is 3.5cm.

∴ The diameter of circle :-

We know that,

$\bigstar \: \boxed{\bf{Diameter \: of \: circle = 2 \times radius}}$

Therefore,

$\bf{\longmapsto \: 2 \times radius} \\ \\ \\ \\ \bf{\longmapsto \: (2 \times 3.5)cm} \\ \\ \\ \\ \bf{\longmapsto \: \boxed{ \bf{ \red{7cm}}}}$

Hence, The diameter of circle is 7cm.

Answer 2

Given :-

• Shape = Circle
• Circumference of the Circle = 22cm

To Find :-

• Diameter of the Circle

Solution :-

❏ For finding the Diameter of the Circle we need the Radius of the Circle, and Circumference of the Circle is given, So we will apply [ Circumference of Circle = 2πr ] to find the Radius of the Circle.

⟾⠀⠀Circumference of Circle = 2πr

⟾⠀⠀22 = 2 × 22/7 × Radius

⟾⠀⠀22 / 2 = 22/7 × Radius

⟾⠀⠀11 = 22/7 × Radius

⟾⠀⠀11 × 7 / 22 = Radius

⟾⠀⠀77 / 22 = Radius

⟾⠀⠀3.5cm = Radius

Now,

❍ Diameter = 2 × Radius

➞ Diameter = 2 × Radius

➞ Diameter = 2 × 3.5

➞ Diameter = 7cm

Thus, Diameter of the Circle = 7cm

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Diagram :-

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\qbezier(2.3,0)(2.121,2.121)(0,2.3)\qbezier(-2.3,0)(-2.121,2.121)(0,2.3)\qbezier(-2.3,0)(-2.121,-2.121)(0,-2.3)\qbezier(2.3,0)(2.121,-2.121)(-0,-2.3)\put(0,0){\line(1,0){2.3}}\put(0.5,0.3){\bf\large 3.5\ cm}\end{picture}$

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