Question

If the circumference of a circle is 44cm and the sum of two sides of square is 22cm ,then

Answer 1

Answer:

c=44cm

therefore,

c =\pi \times d

\pi =  \frac{22}{7}  

44 =d \times \frac{22}{7}  

\frac{44}{d}  =  \frac{22}{7}  

44 \times 7 = 22 \times d

308 = 22d

\frac{308}{22} = d  

d = 14

diameter=14

raidus=14/2

=7cm

area \: of \: circle = \pi \times  {r}^{2}  

=  \frac{22}{7}  \times 7 \times 7

= 22 \times 7

=154cm²

we know that square has equal length sides..,

therefore..,

x + x = 22

x = 11cm

area \: of \: square = {side}^{2}  

=  {11}^{2}  

= 121 {cm}^{2}  

so,

option B) area of circle > area of square is right.

Step-by-step explanation: