Math, asked by amit22223, 6 months ago

If the circumference of a circle is 55 cm then what is its radius and diameter?

Answers

Answered by MoodyCloud
7
  • Radius of circle is 8.75 cm.
  • Diameter of circle is 17.5 cm.

Step-by-step explanation:

Given:-

  • Circumference of circle is 55 cm.

To find:-

  • Radius and Diameter of circle.

Solution:-

  • We will use circumference of circle for finding radius of circle.
  • Then by using radius we will find diameter of circle.

We know,

Circumference of circle = 2πr

Where,

  • r is radius of circle.

Put, circumference of circle in formula :

 \longrightarrow 55 = 2πr

 \longrightarrow 55 = 2 × 22/7 × r

 \longrightarrow 55 × 7 = 2 × 22 × r

 \longrightarrow 385 = 44 × r

 \longrightarrow 385/44 = r

 \longrightarrow r = 8.75

So,

Radius of circle is 8.75 cm.

We also know that,

Diameter = 2 × radius

So,

= 2 × 8.75

= 17.5

Therefore,

Diameter of circle is 17.5 cm.

Answered by Anonymous
4

Correct Question-:

  • If the circumference of a circle is 55 cm . Then what is its radius and diameter?

AnswEr-:

  • \underline{\boxed{\star{\sf{\purple{Radius\:of\:Circle=8.75cm }}}}}
  • \underline{\boxed{\star{\sf{\purple{Diameter \:of\:Circle\:=\:17.5cm}}}}}

Explanation-:

Given-:

  • The circumference of a circle is 55 cm.

To Find -:

  • Diameter and Radius of Circle.

Now,

  • \underline{\boxed{\star{\sf{\purple{Circumference\:of\:Circle\:=\:2× \pi × Radius}}}}}

Here ,

  • Radius = ??
  • Circumference of Circle = 55 cm .
  • π = 22/7

Now ,

  • \implies {\large{\sf{ 55cm = 2 × \frac {22}{7} ×  Radius   }}}
  • \implies {\large{\sf{ 55 × 7 = 2 × 22 ×  Radius   }}}
  • \implies {\large{\sf{  385 = 44 ×  Radius   }}}
  • \implies {\large{\sf{  \frac {385}{44} = Radius   }}}
  • \implies {\large{\sf{ 8.75cm = Radius   }}}

Therefore,

  • \underline{\boxed{\star{\sf{\purple{Radius\:of\:Circle=8.75cm }}}}} -----[1]

Now ,

  • \underline{\boxed{\star{\sf{\purple{Diameter \:of\:Circle\:=\:2×  Radius}}}}}

Here ,

  • Radius = 8.75 cm ______[ From 1]

Now ,

  • \implies {\large{\sf{ Diameter_{(Circle)}= 2 ×  8.75   }}}
  • \implies {\large{\sf{ Diameter_{(Circle)}= 17.5 cm   }}}

Therefore,

  • \underline{\boxed{\star{\sf{\purple{Diameter \:of\:Circle\:=\:17.5cm}}}}}

Hence ,

  • \underline{\boxed{\star{\sf{\purple{Radius\:of\:Circle=8.75cm }}}}}
  • \underline{\boxed{\star{\sf{\purple{Diameter \:of\:Circle\:=\:17.5cm}}}}}

☆ Figure related to this -:

\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\qbezier(2.3,0)(2.121,2.121)(0,2.3)\qbezier(-2.3,0)(-2.121,2.121)(0,2.3)\qbezier(-2.3,0)(-2.121,-2.121)(0,-2.3)\qbezier(2.3,0)(2.121,-2.121)(-0,-2.3)\put(0,0){\line(1,0){2.3}}\put(0.5,0.3){\bf\large 8.75\ cm}\end{picture}

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