Question

If the class mark is 25 and class width is 10 ,then the classinterva is 10 find the class

Answer 1

Answer:

Step-by-step explanation:

Let the lower limit be X and the upper limit be Y

According to the first condition

X+Y/2 = 25

X + Y = 50

According to the second condition

Y - X = 10

Therefore X - Y = -10

Solve these equations and you get

X = 20, substitute this value in any of the above equations

20 + Y = 50

Y = 50 - 20

Y = 30

Therefore the class is 20 - 30

Answer 2

Answer:

Let Lower Limit be L

∴  Upper Limit =L+10      [ Since,  Class Width =10]

Now, we know that  

ClassMark=(LowerLimit+UpperLimit)÷2

∴  (L+L+10)÷2=25           [Class Mark 25 given]

⇒  2L+10=50

⇒  2L=40

⇒  L=20

∴  Lower Limit of the class =20

Upper Limit of the class =20+10=30

The required class is 20−30

(pls mark brainliest)