if the class mark of a class interval is 17.5 whose lower limit is 15.find it's upper limit.
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Answered by
1
upper limit is 20
as class mark= {lower limit+upper limit}÷3
as class mark= {lower limit+upper limit}÷3
Bhaavya1:
no sorry 2
Answered by
2
Let the upper limit be x
We know that,
class mark = ( upper limit+ lower limit)/2
From the condition we get,
(x +15)/2 = 17.5
=> x +15 = 17.5 ×2
=> x = 35 -15 = 20
Hence upper limit is 20
Hope this helps.
Please mark me brainliest
We know that,
class mark = ( upper limit+ lower limit)/2
From the condition we get,
(x +15)/2 = 17.5
=> x +15 = 17.5 ×2
=> x = 35 -15 = 20
Hence upper limit is 20
Hope this helps.
Please mark me brainliest
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