Social Sciences, asked by Mingyurpaldon2736, 1 year ago

If the coefficient of 2nd 3rd and 4th terms in e expansion of (1 + x)n are in A.P., then the value of n is
(A) 2
(B) 7
(C) 11
(D) 14

Answers

Answered by sushantsagardask
0

Answer:

Explanation:

Coefficient of (r+1)th in the expansion of (1+x)

Coefficient of (r+1)th in the expansion of (1+x) n

Coefficient of (r+1)th in the expansion of (1+x) n is

Coefficient of (r+1)th in the expansion of (1+x) n is n

Coefficient of (r+1)th in the expansion of (1+x) n is n C

Coefficient of (r+1)th in the expansion of (1+x) n is n C r

Coefficient of (r+1)th in the expansion of (1+x) n is n C r

Coefficient of (r+1)th in the expansion of (1+x) n is n C r

Coefficient of (r+1)th in the expansion of (1+x) n is n C r Given 2nd, 3rd and 4th terms are in A.P

Coefficient of (r+1)th in the expansion of (1+x) n is n C r Given 2nd, 3rd and 4th terms are in A.P⇒2.

Coefficient of (r+1)th in the expansion of (1+x) n is n C r Given 2nd, 3rd and 4th terms are in A.P⇒2. n

Coefficient of (r+1)th in the expansion of (1+x) n is n C r Given 2nd, 3rd and 4th terms are in A.P⇒2. n C

Coefficient of (r+1)th in the expansion of (1+x) n is n C r Given 2nd, 3rd and 4th terms are in A.P⇒2. n C 2

Coefficient of (r+1)th in the expansion of (1+x) n is n C r Given 2nd, 3rd and 4th terms are in A.P⇒2. n C 2

Coefficient of (r+1)th in the expansion of (1+x) n is n C r Given 2nd, 3rd and 4th terms are in A.P⇒2. n C 2 =

Coefficient of (r+1)th in the expansion of (1+x) n is n C r Given 2nd, 3rd and 4th terms are in A.P⇒2. n C 2 = n

Coefficient of (r+1)th in the expansion of (1+x) n is n C r Given 2nd, 3rd and 4th terms are in A.P⇒2. n C 2 = n C

Coefficient of (r+1)th in the expansion of (1+x) n is n C r Given 2nd, 3rd and 4th terms are in A.P⇒2. n C 2 = n C 1

Coefficient of (r+1)th in the expansion of (1+x) n is n C r Given 2nd, 3rd and 4th terms are in A.P⇒2. n C 2 = n C 1

Coefficient of (r+1)th in the expansion of (1+x) n is n C r Given 2nd, 3rd and 4th terms are in A.P⇒2. n C 2 = n C 1 +

Coefficient of (r+1)th in the expansion of (1+x) n is n C r Given 2nd, 3rd and 4th terms are in A.P⇒2. n C 2 = n C 1 + n

Coefficient of (r+1)th in the expansion of (1+x) n is n C r Given 2nd, 3rd and 4th terms are in A.P⇒2. n C 2 = n C 1 + n C

Coefficient of (r+1)th in the expansion of (1+x) n is n C r Given 2nd, 3rd and 4th terms are in A.P⇒2. n C 2 = n C 1 + n C 3

Coefficient of (r+1)th in the expansion of (1+x) n is n C r Given 2nd, 3rd and 4th terms are in A.P⇒2. n C 2 = n C 1 + n C 3

Coefficient of (r+1)th in the expansion of (1+x) n is n C r Given 2nd, 3rd and 4th terms are in A.P⇒2. n C 2 = n C 1 + n C 3

Coefficient of (r+1)th in the expansion of (1+x) n is n C r Given 2nd, 3rd and 4th terms are in A.P⇒2. n C 2 = n C 1 + n C 3 ⇒n(n−1)=n+

Coefficient of (r+1)th in the expansion of (1+x) n is n C r Given 2nd, 3rd and 4th terms are in A.P⇒2. n C 2 = n C 1 + n C 3 ⇒n(n−1)=n+ 6

Coefficient of (r+1)th in the expansion of (1+x) n is n C r Given 2nd, 3rd and 4th terms are in A.P⇒2. n C 2 = n C 1 + n C 3 ⇒n(n−1)=n+ 6n(n−1)(n−2)

Coefficient of (r+1)th in the expansion of (1+x) n is n C r Given 2nd, 3rd and 4th terms are in A.P⇒2. n C 2 = n C 1 + n C 3 ⇒n(n−1)=n+ 6n(n−1)(n−2)

Coefficient of (r+1)th in the expansion of (1+x) n is n C r Given 2nd, 3rd and 4th terms are in A.P⇒2. n C 2 = n C 1 + n C 3 ⇒n(n−1)=n+ 6n(n−1)(n−2)

Coefficient of (r+1)th in the expansion of (1+x) n is n C r Given 2nd, 3rd and 4th terms are in A.P⇒2. n C 2 = n C 1 + n C 3 ⇒n(n−1)=n+ 6n(n−1)(n−2) ⇒6(n−1)=6+n

Coefficient of (r+1)th in the expansion of (1+x) n is n C r Given 2nd, 3rd and 4th terms are in A.P⇒2. n C 2 = n C 1 + n C 3 ⇒n(n−1)=n+ 6n(n−1)(n−2) ⇒6(n−1)=6+n 2

Coefficient of (r+1)th in the expansion of (1+x) n is n C r Given 2nd, 3rd and 4th terms are in A.P⇒2. n C 2 = n C 1 + n C 3 ⇒n(n−1)=n+ 6n(n−1)(n−2) ⇒6(n−1)=6+n 2 −3n+2

Coefficient of (r+1)th in the expansion of (1+x) n is n C r Given 2nd, 3rd and 4th terms are in A.P⇒2. n C 2 = n C 1 + n C 3 ⇒n(n−1)=n+ 6n(n−1)(n−2) ⇒6(n−1)=6+n 2 −3n+2⇒n

2

−9n+14=0⇒n=7

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