Physics, asked by vamsisudha9179, 1 year ago

If the coefficient of conductivity of aluminium is 0.5cal/cm-sec-°C, then in order to conduct10 cal/sec-cmin the steady state, the temperaturegradient in aluminium must be(1) 5°C/cm(2) 10°C/cm(3) 20°C/cm(4) 10.5°C/cm​

Answers

Answered by bparihar184
1

Answer:

you don't know 20 805ngsnc

Answered by handgunmaine
5

The temperature gradient in aluminium is 20\ ^ oC/cm \ .

Given :

Coefficient of conductivity of aluminium , K=0.5\ cal/cm-sec-^oC.

We need to find the temperature gradient in order to conduct 10 \ cal/sec - cm^2.

We know, Temperature gradient is equal to change in temperature per unit length .

Therefore, Temperature gradient = \dfrac{\Delta T}{\Delta x}  ( here \Delta T and \Delta x is change in temperature and length respectively ).

Now, \dfrac{\Delta T}{\Delta x}=\dfrac{1}{K }\dfrac{\Delta Q}{ \Delta t\ A}      ..... equation 1.

Value of \dfrac{\Delta Q}{ \Delta t\ A} \ is \ given \ as : 0.5\ cal/sec-cm^2

Putting value of K and \dfrac{\Delta Q}{ \Delta t\ A}  in equation 1 , we get :

\dfrac{\Delta T}{\Delta x}=\dfrac{10}{0.5}=20\ ^oC/cm\ .

Therefore, option 3) is correct .

Hence, this is the required solution .

Learn More :

Expansion of solids .

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