if the coefficient of friction between a car's tyre and a road way is 0.62, what is the least distance in which the car can accelerate from rest to 20.7m/s
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F= mu*N
F= friction force
mu= coefficient of kinetic friction
N =mg = contact force
Fnet= ma
a=mu*g
a= 0.62*9.81
initial velocity,u=0
final velocity,v=20.7 m/s
v^2 = 2*a*s
s= v^2/2a
s= answer
F= friction force
mu= coefficient of kinetic friction
N =mg = contact force
Fnet= ma
a=mu*g
a= 0.62*9.81
initial velocity,u=0
final velocity,v=20.7 m/s
v^2 = 2*a*s
s= v^2/2a
s= answer
Lucario168:
Thank you
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