Question

If the coefficient of friction between the block of mass 5 kg and wall is 0.5, then minimum force F required to hold the block with the wall is
(g = 10 m/s2)​

Answer 1

Explanation:

Frictional force (Ff)= coefficient of friction (μ) × Normal Force (Fn)

Ff = μ × Fn

Fn=mass × acceleration due to gravity (g)

Given:

m = 5 kg

μ = 0.5

g = 10 m/s²

Required:

Ff = ?

Solution:

Fn = m × g

Fn = 5 kg × 10 m/s²

Fn = 50 kg m/s²

Plug in the values of Fn in the formula:

Ff = μ × Fn

Ff = 0.5 × 50 kg m/s²

Ff = 25 kg m/s² or Ff = 25 N ANSWER

Answer 2

Answer:

100 N

Explanation:

N=F

muN=mg

muF=5×10

F=50/0.5

F=100N