Question

if the common difference of A.p is 3 than a23-a15 ​

Answer 1

Answer:

24

Step-by-step explanation:

In APs, nth terms is given by a + (n - 1)d, where a is first term and d is common difference.

So, here:

= > a(23) - a(15)

= > [ a + (23 - 1)d ] - [ a + (15 - 1)d ]

= > (a + 22d) - (a + 14d)

= > a + 22d - a - 14d

= > 8d

= > 8(3) { d = 3}

= > 24

Answer 2

ᎯᏁᏕᏯᎬᏒ

$~~\sf a_{23} - a_{15} = (a + 22d) - (a + 14d)$

$↣\sf a_{23} - a_{15} =a + 22d - a - 14d$

$↣\sf a_{23} - a_{15} =22d - 14d$

$\sf Putting~ value:~ \red{d=3}$

$↣\sf a_{23} - a_{15} =(22 \times 3 )- (14 \times 3)$

$↣ \sf a_{23} - a_{15} =66 - 42$

${\therefore}~~\boxed{\purple {\sf {a_{23} - a_{15} =24}}}$