If the common difference of an ap is 3 find a 20 - a15
Answers
Answered by
1
Answer:
15
Step-by-step explanation:
a20-a15=a+19d-a-14d
=5d
=5×3
=15
Answered by
0
Answer:
Let the first term of the AP be a.
an = a(n − 1)d
a₂₀ – a₁₅ = [a + (20 – 1)d] – [a + (15 – 1)d]
= 19d – 14d
= 5d
= 5 × 3
= 15
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