Question

If the common difference of an AP is 5, then (18th term- 13th term) is

Answer 1

Answer:

25

Step-by-step explanation:

the common difference of AP i.e., d = 5

Now, a18 - a13 = a + (18-1) d - [a+(13-1)d] [∵an = a + (n-1)d]

= a + 17 × 5 - a - 12 × 5

= 85 - 60 = 25

Answer 2

18th term - 13th term = 25

Given :

The common difference of an AP is 5

To find :

18th term - 13th term

Concept :

If in an arithmetic progression

First term = a

Common difference = d

Then nth term of the AP

= a + ( n - 1 )d

Solution :

Step 1 of 2 :

Find 18th term and 13th term

Let first term = a

Common Difference = d = 5

18th term = a₁₈ = a + (18 - 1)d = a + 17d

13th term = a₁₃ = a + (13 - 1)d = a + 12d

Step 2 of 2 :

Find the value of 18th term - 13th term

18th term - 13th term

= (a + 17d) - (a + 12d)

= a + 17d - a - 12d

= 5d

= 5 × 5

= 25

Hence 18th term - 13th term = 25

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