Question

If the common difference of an ap is-6 then what is a16-a12

Answer 1

Answer:

here,

common difference (d)= -6

first term = a [supposition]

16th term = a+ (16-1) × d= a + 15d

12th term = a + (12-1) × d = a + 11d

$a _{16} - a _{12}$

= (a +15d) - (a + 11d)

= a + 15d - a - 11d

= 4d

= 4× (-6)

= -24