Question

If the common difference of AP is2 then a¹⁰-a⁵

Answer 1

Given :

• Common difference (d) = 2

To find :

• a₁₀ - a₅

Solution :

We know that ,

$\sf a_{n} \: = \: a \: + \: (n-1)d$

Where ,

• n = number of term
• a = first term
• d = common difference

$\sf a_{10} \: = \: a \: + \: (10-1)d\\ \sf \implies a_{10} \: = \: a \: + \: 9d$

Also,

$\sf a_{5} \: = \: a \: + \: (5 - 11)d\\ \sf \implies a_{5} \: = \: a \: + \: 4d$

Now , putting values in a₁₀ - a₅

We get,

a₁₀ - a₅ = [ a+9d ] - [ a+4d]

a₁₀ - a₅ = a + 9d - a - 4d

a₁₀ - a₅ = 5d

a₁₀ - a₅ = 5×(2)

a₁₀ - a₅ = 10

ANSWER = 10

Answer 2

this is the question for class 10 ch arithmetic progression

from the book Rd sharma pg no 9.24

q no 21