If the common different of an AP is 3, then the value of a20 - a15 =?
A) 5
B) 3
C) 15
D) 20
Answers
Answered by
10
We know that,
an=a+(n-1)d
So,a20=a+(20-1)(3)
a20=a+19(3)
a20=a+57
Similarly, a15=a+14d
a15=a+14(3)
a15=a+42
Now,a20-a15=(a+57)-(a+42)
=a+57-a-42
=57-42
=15
an=a+(n-1)d
So,a20=a+(20-1)(3)
a20=a+19(3)
a20=a+57
Similarly, a15=a+14d
a15=a+14(3)
a15=a+42
Now,a20-a15=(a+57)-(a+42)
=a+57-a-42
=57-42
=15
Answered by
3
Hey Mate ✌
↪ Here's your answer friend,
Given : Common difference (d) ==> 3
Let a be the first term
==> a20 = a + 19d
and
==> a15 = a + 14d
Now,
a20 - a15
==> (a + 19d) - (a + 14d)
==> a + 19d - a -14d
==> 5d
Now by substituting d = 3
we get,
5(3) = 15 is the required answer.
⭐ Hope it helps you : ) ⭐
↪ Here's your answer friend,
Given : Common difference (d) ==> 3
Let a be the first term
==> a20 = a + 19d
and
==> a15 = a + 14d
Now,
a20 - a15
==> (a + 19d) - (a + 14d)
==> a + 19d - a -14d
==> 5d
Now by substituting d = 3
we get,
5(3) = 15 is the required answer.
⭐ Hope it helps you : ) ⭐
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