Question

If the common diffrence of ap is 5 then what is a18_a 13​

Answer 1

Step-by-step explanation:

(c) Given, the common difference of AP i.e., d = 5

Now, a18 - a13 = a + (18-1) d - [a+(13-1)d]  [∵an = a + (n-1)d]

= a + 17 × 5 - a - 12 × 5  

= 85 - 60 = 25  

Answer 2

Answer:

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25

Step-by-step explanation:

Given,

d = 5

we have nth term, $a_{n} = a+(n-1)d$

we know, $a_{18} = a+17d$

and $a_{13} = a+12d$

so, $a_{18} - a_{13} = a+17d-(a+12d)$

                    $=17d-12d\\=5d$

                    = 5 x 5

                    = 25

so, a18-a13 = 25