Question

if the common factor(ax²+bx+c) and (bx²+ax+c) is (x+2) then?
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Answer 1

Answer:

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Step-by-step explanation:

ax^{2}+bx+2c+bx^{2}+ax=x+2

ax^{2}+2c+bx^{2}+ax=x+2-bx

ax^{2}+ax=x+2-bx-2c-bx^{2}

\left(x^{2}+x\right)a=2-2c+x-bx-bx^{2}

a=\frac{2-2c+x-bx-bx^{2}}{x\left(x+1\right)}