Question

if the common ratio of G.P. is 2/3 and sum to infinity is 12. find the first term
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Answer 1

Answer:

$sum \: of \: infinite \: gp = \frac{a}{1 - r} \\ 12 = \frac{a}{1 - \frac{2}{3} } \\ 12 = \frac{3a}{3 - 2} \\ a = \frac{12}{3} = 4$