Question

If the common solution of the equations 3x + 2y = 5 and 5x – 2y = 3 satisfies y = mx – 3, find

the value of ‘m​

Answer 1

Step-by-step explanation:

Given,

3x + 2y = 5

By trial and error method,

Let 'x' and 'y' be 1

LHS=. RHS = 5

=3(1) + 2(1)

=3+2

=5

Since LHS = RHS

therefore, x = 1 and y= 1

And also given, 5x - 2y = 3

By trial and error method,

Let 'x' and 'y' be 1

LHS =

=5(1) - 2(1)

=5-2=3

Since LHS = RHS

therefore, x = 1 and y= 1

Now,

= y = mx - 3

= 1 = m(1) -3

= m(1) - 3=1

= m - 3 = 1

= m = 1 + 3

= m = 4

Therefore, the value of m = 4

Hope It helps