Question

If the complement of an angle is
one fifth of its supplement,find the angle

Answer 1

Let the angle be x.
Complement of the angle = (90-x)°
Supplement of the angle = (180-x)°
According to the question..
90-x=1/5× (180-x)
90-x= (180-x) /5
5 (90-x) =180-x
450-5x=180-x
450-180=-x+5x
270=4x
x=270/4
x=67. 5°
Hope this helps.

Answer 2

Answer:

Required Angle is 15°

Step-by-step explanation:

Let x be the the complement angle.

Angle = $\frac{1}{5}\times x$

According to the Question,

$x+\frac{1}{5}\times x=90$

$x+\frac{x}{5}=90$

$\frac{5x+x}{5}=90$

$6x=90\times5$

$6x=450$

$6x=450$

$x=\frac{450}{6}$

$x=75$

Angles = $\frac{75}{x}=15^{\circ}$

Therefore, Required Angle is 15°