Question

If the components of air are nitrogen
(78%), oxygen (20%), Argon (1%)
and carbon dioxide (1%) by volume,
what would be the molecular mass of air
in amu?​

Answer 1

Nitrogen: 78.084%

Nitrogen: 78.084%Oxygen: 20.946%

Nitrogen: 78.084%Oxygen: 20.946%Argon: 0.934%

Nitrogen: 78.084%Oxygen: 20.946%Argon: 0.934%Carbon dioxide: 0.03%

Nitrogen: 78.084%Oxygen: 20.946%Argon: 0.934%Carbon dioxide: 0.03%If you add these up you get: 78.084 + 20.946 + 0.934 + 0.03 = 99.994% (the remaining material 100 - 99.994 = 0.006% consists of trace amounts of other gases)

Nitrogen: 78.084%Oxygen: 20.946%Argon: 0.934%Carbon dioxide: 0.03%If you add these up you get: 78.084 + 20.946 + 0.934 + 0.03 = 99.994% (the remaining material 100 - 99.994 = 0.006% consists of trace amounts of other gases)These percentages are percentage volume and one mole of gas at stand temperature and pressure occupies 22.4 liters (but that is really irrelevant to this question as the volumes cancel).

The molar mass of dry air with oxygen, nitrogen and the other components as indicated below is 28.9647 g/mol. Composition and content of each gas in air is given in the figures and the table below.

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