Question

If the components of the air are N2, 78%; O2, 21%; Ar, 0.9% and CO2, 0.1% by volume, what would be the molecular mass of air?

Answer 1

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$\implies$ Given Compositions N2, 78%; O2, 21%; Ar, 0.9% and CO2, 0.1% by volume.

$\implies$ We need to follow Avagadro Principle.

$\implies$The molar ratios are also the volume ratios for the gases that is Avogadro’s principle.

$\implies$ 1 Avagadro Number = 6.023×10^23 particles or sub-units

$\implies$ Molecular mass of air by calculations ----

$\implies$= (78×28 + 21×32 + 0.9×40 + 0.1×44)/(78 + 21 + 0.9 + 0.1)

$\implies$ Furthur solving ,

$\implies$= 28.964.

Answer 2

Answer:

28.964 is answer

thanks for asking hope it helps