Math, asked by thungala123, 1 month ago

If the compound interest is paid on an annual basis over Rs.5,400, it is Rs.9,600 in 2 years 6 months. With the same annual interest rate for how long can Rs. 1,92,000​

Answers

Answered by srimathagranites
0

Answer:

C.I. for the third year = Rs. 1,452.

C.I. for the second year = Rs. 1,320

∴ S.I on Rs. 1,320 for one year = Rs. 1,452− Rs. 1,320= Rs. 132.

Rate of interest =  

1,320

132×100

=10%.

Let the original money be Rs. P.

Amount after 2 year − amount after one year =C.I. for second year.

P(1+  

100

10

)  

2

−P(1+  

100

10

)=1,320

P[(  

100

110

)  

2

−  

100

110

]=1,320

⇒P[(  

10

11

)  

2

−  

10

11

]=1,320⇒P(  

100

121

−  

10

11

)= Rs. 1,320

⇒P×  

100

11

=Rs.1,320⇒P=  

11

1,320×100

= Rs. 12,000

∴ Rate of interest =10%

and Original sum of money = Rs. 12,000C.I. for the third year = Rs. 1,452.

C.I. for the second year = Rs. 1,320

∴ S.I on Rs. 1,320 for one year = Rs. 1,452− Rs. 1,320= Rs. 132.

Rate of interest =  

1,320

132×100

=10%.

Let the original money be Rs. P.

Amount after 2 year − amount after one year =C.I. for second year.

P(1+  

100

10

)  

2

−P(1+  

100

10

)=1,320

P[(  

100

110

)  

2

−  

100

110

]=1,320

⇒P[(  

10

11

)  

2

−  

10

11

]=1,320⇒P(  

100

121

−  

10

11

)= Rs. 1,320

⇒P×  

100

11

=Rs.1,320⇒P=  

11

1,320×100

= Rs. 12,000

∴ Rate of interest =10%

and Original sum of money = Rs. 12,000

Step-by-step explanation:

Similar questions