Accountancy, asked by Anonymous, 26 days ago

If the compound interest on a certain sum for two years at 10% p.a. is Rs 3200 and the simple interest on other Sum at the same rate for two years will be 12000. What is the sum of the principal?​

Answers

Answered by CHATURVEDIAYUSHI789
2

Answer:

hope it helps you siso...

Attachments:
Answered by tennetiraj86
3

Explanation:

Given :-

the compound interest on a certain sum for two years at 10% p.a. is Rs 3200 and the simple interest on other Sum at the same rate for two years will be 12000.

To find :-

What is the sum of the principal?

Solution :-

Let the principle be Rs. X

Rate of interest (R) = 10%

Time =2 years

Compound interest = Rs. 3200

We know that

A = P[1+(R/100)]^n

On Substituting these values in the above formula

=> A = X[1+(10/100)]²

=> A = X[1+(1/10)]²

=> A = X[(10+1)/10]²

=> A = X(11/10)²

=> A = X(121/100)

=> A = 121X/100

Amount = Rs. 121X/100

We know that

A = P + I

=> P = A - I

=> X = (121X/100)-3200

=> X = (121X-320000)/100

=> X×100 = 121X-320000

=> 100X = 121X-320000

=> 100X-121X = -320000

=> -21X = -320000

=> 21 X = 320000

=> X = 320000/21

=> X = 15238.095

=> X = Rs. 15238

and

Rate of interest = 10%

Simple Interest = Rs. 12000

Time = 2 years

Let the Principle be Rs. X

We know that

Simple Interest = PTR/100

On Substituting these values in the above formula then

=> 12000 = (X×2×10)/100

=> 12000 = 20X/100

=> 12000 = X/5

=> X = 12000×5

=> X = Rs. 60000

The principle in the first condition = Rs. 15238

The principle in the second condition =

Rs. 60000

The sum of the principles

= 15238+60000

= Rs. 75238

Answer :-

The sum of the principles for the given problem is Rs. 75238

Used formulae:-

  • A = P[1+(R/100)]^n

  • A = P + I

  • Simple Interest = PTR/100

Where,

  • I = Interest

  • A = Amount

  • P = Principle

  • T = Time

  • R = Rate of Interest

  • n = Number of times the compound interest is calculated.

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