Question

if the compound interest on the principal of rs 1700 for 2 years is 210.12 ,what is the rate of interest per annumm​

Answer 1

ANSWER

ANSWERSimple Interest, S.I. = Rs. 1260 = 100PR×2 =  50PR          -(i)

ANSWERSimple Interest, S.I. = Rs. 1260 = 100PR×2 =  50PR          -(i)Compound Interest, C.I. = Amount(A) - Principle(P)

ANSWERSimple Interest, S.I. = Rs. 1260 = 100PR×2 =  50PR          -(i)Compound Interest, C.I. = Amount(A) - Principle(P)=P(1+100R)2 - P = PR(R/10000+1/50)=Rs.1323         -(ii)

ANSWERSimple Interest, S.I. = Rs. 1260 = 100PR×2 =  50PR          -(i)Compound Interest, C.I. = Amount(A) - Principle(P)=P(1+100R)2 - P = PR(R/10000+1/50)=Rs.1323         -(ii)Dividing (ii) by (I),

ANSWERSimple Interest, S.I. = Rs. 1260 = 100PR×2 =  50PR          -(i)Compound Interest, C.I. = Amount(A) - Principle(P)=P(1+100R)2 - P = PR(R/10000+1/50)=Rs.1323         -(ii)Dividing (ii) by (I),200R+1 = 12601323

ANSWERSimple Interest, S.I. = Rs. 1260 = 100PR×2 =  50PR          -(i)Compound Interest, C.I. = Amount(A) - Principle(P)=P(1+100R)2 - P = PR(R/10000+1/50)=Rs.1323         -(ii)Dividing (ii) by (I),200R+1 = 12601323⇒Rate,R=10%p.a.

ANSWERSimple Interest, S.I. = Rs. 1260 = 100PR×2 =  50PR          -(i)Compound Interest, C.I. = Amount(A) - Principle(P)=P(1+100R)2 - P = PR(R/10000+1/50)=Rs.1323         -(ii)Dividing (ii) by (I),200R+1 = 12601323⇒Rate,R=10%p.a.Now, 100PRT=1260

ANSWERSimple Interest, S.I. = Rs. 1260 = 100PR×2 =  50PR          -(i)Compound Interest, C.I. = Amount(A) - Principle(P)=P(1+100R)2 - P = PR(R/10000+1/50)=Rs.1323         -(ii)Dividing (ii) by (I),200R+1 = 12601323⇒Rate,R=10%p.a.Now, 100PRT=1260⇒ 100P×10×2=1260

ANSWERSimple Interest, S.I. = Rs. 1260 = 100PR×2 =  50PR          -(i)Compound Interest, C.I. = Amount(A) - Principle(P)=P(1+100R)2 - P = PR(R/10000+1/50)=Rs.1323         -(ii)Dividing (ii) by (I),200R+1 = 12601323⇒Rate,R=10%p.a.Now, 100PRT=1260⇒ 100P×10×2=1260⇒ Principal or Sum P = Rs.6,300