If the concentration of glucose (C6H1206) in blood is 0.9 gl-1, what will be
the molarity of glucose in blood ?
(A) 5 m (B) 50 m (C) 0.005 m (D) 0.5 m
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Answer:
molar mass of glucose(C6H12O6) = 12*6+1*12+16-6=180
MOLARITY= concentration in gL-1/Molar mass = 0.90 gL-1/180 g mol-1=0.005M
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