If the concentration of glucose (C6H12O6) in blood is 0.9 g L^–1, what will be the molarity of glucose in blood?
(i) 5 M
(ii) 50 M
(iii) 0.005 M
(iv) 0.5 M
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(iii)0.0005M
molecular weight of glucose = 180 G
Given = 0.9G
Molarity= No. of moles of solute/Vol. of solvent in Litres
molecular weight of glucose = 180 G
Given = 0.9G
Molarity= No. of moles of solute/Vol. of solvent in Litres
Answered by
2
Explanation:
Concentration of glucose in blood = 0.9g/L Number of moles of glucose = 0.9180=0.005 moles
Volume of solution = 1 litre
Hence, Molarity = Number of molesVolume of solution in litres = 0.0051= 0.005M
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