Chemistry, asked by xyzxyzxyz23, 4 months ago

if the concentration of pbi2 is found to be 2×10^-2 mol/lit then calculate it's solubility product​

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Answered by drishtisingh156
5

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Answered by LakshyaBisht
0

Answer:

PbI_2 → Pb^+2 + 2I^−

S 2S

K_sp =4S^3

4S^3 =3.2×10^−8

;S=2×10^−3M

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