If the constant term in the expansion of
is 112 find a.
Answers
Answered by
3
Answer:
(1+x)
10
(
x
1
+1)
12
=
x
(
12)
1
(1+x)
22
T
r+1
=
22
C
r
x
r−12
Hence the term independent of x will be the constant term.
r−12=0
⇒r=12
Hence the 13
th
term from the starting will be the constant term.
Therefore
The corresponding binomial coefficient
=
22
C
12
Step-by-step explanation:
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