Question

if the coordinates of one end of a diameter of a circle are (2,3) and the coordinates of its centre are (-2,5), then find the coordinates of the other end of the diameter.

Answer 1

Answer:

The coordinates of the other end of the diameter is (-6,7).

Step-by-step explanation:

Let the coordinates of the other end of the diameter be (x,y).

It is given that the coordinates of one end of a diameter of a circle are (2,3) and the coordinates of its centre are (-2,5).

The center is the midpoint of end points of a diameter.

$Center=(\frac{2+x}{2},\frac{3+y}{2})$

$(-2,5)=(\frac{2+x}{2},\frac{3+y}{2})$

On compering both the sides.

$\frac{2+x}{2}=-2$

$2+x=-4$

$x=-6$

The value of x is -6.

$\frac{3+y}{2}=5$

$3+y=10$

$y=7$

The value of y is 7.

Therefore the coordinates of the other end of the diameter is (-6,7).

Answer 2

Answer:

hey there its a step explanation