if the coordinates of opposite vertices of a square are (1,3) and (6,0) the length of a side of a square is?
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Lenght of opposite verteces = diagonal of square
=> √(1-6)² + (3-0)²= √(-5)² + (3)²= √35 units.
we know that.,
diagonal of square =√2 x side
=> √35=√2 x side => side = √35/√2=√70/2
units.
So length of side of square is √70/2.
Hope it will help you
=> √(1-6)² + (3-0)²= √(-5)² + (3)²= √35 units.
we know that.,
diagonal of square =√2 x side
=> √35=√2 x side => side = √35/√2=√70/2
units.
So length of side of square is √70/2.
Hope it will help you
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