Question

if the coordinates of points P(-2,3) and Q(-3,5) then the value of (ordinate of Q+ abscissa of P) Is
(a) 3
(b) 8
(c) -5
(d) 0​

Answer 1

Given→

P(-2,3) and Q(-3,5)

To find →

(ordinate of Q+ abscissa of P)

Solution→

Ordinate → coordinate of y axis of any point

Abscissa → coordinate of x axis of any point

(ordinate of Q+ abscissa of P)

= ( 5+ (-2) )

= 3

Ans(a)

Hope it's helpful