If the coordinates of the centroid of a triangle are (2/3,5/3) and the coordinates of two vertices of the triangle are (-1, 0) and (3, 0), then what are the coordinates of the third vertex of the triangle? Pls solve faste
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Centroid of a triangle with vertices (x1,y1);(x2,y2) and (x3,y3) is calculated by the formula (3x1+x2+x3,3y1+y2+y3)
Let the third vertex of the triangle be (x,y)
So, centroid =(3−7+8+x,36+5+y)=(1,3)
=(31+x,311+y)=(1,3)
=>1+x=3;11+y=9
x=2;y=−2
Hence the third vertex of the triangle is (2,−2)
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