Question

If the coordinates of the centroid of ∆ABC are (-2,3) and those of A and B are, (0,2) and (4,-1) respectively. Find the coordinates of C.
{Hint:Let C be (x, y)
Then
$\frac{x + 0 + 4}{3} = - 2$
and
$\frac{y + 2 - 1}{3} = 3$
}​

Answer 1

Answer:

centroid = [( x1 + x2 + x3)/3 , ( y1 + y2 + y3 )/3]

centroid for given points is ( -2 , 3 )

(-2 , 3) = [(0+4+x)/3 , (2-1+y)/3]

equal x cordinates of lhs and rhs

-2 = (4 + x) / 3 , (1 + y) / 3 = 3

4 + x = -6 , 1 + y = 9

x = -10 , y = 8