Question

if the coordinates of the mid-points of the sides of triangle are (2,1) (3,-5) and (6,4). find its centroid.

Answer 1

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Answer 2

Answer:

$Centroid \: of\:the \: triangle\\=\left(\frac{11}{3},0\right)$

Step-by-step explanation:

if the coordinates of the mid-points of the sides of triangle are (2,1) (3,-5) and (6,4)

$Let (x_{1},y_{1})=(2,1)\\</p><p>(x_{2},y_{2})=(3,-5)\\and\:</p><p>(x_{3},y_{3})=(6,4)$

$Centroid \: of\:the \: triangle\\=\left(\frac{x_{1}+x_{2}+x_{3}}{3},\frac{y_{1}+y_{2}+y_{3}}{3}\right)\\=\left(\frac{2+3+6}{3},\frac{1-5+4}{3}\right)\\=\left(\frac{11}{3},\frac{0}{3}\right)\\=\left(\frac{11}{3},0\right)$

Therefore,

$Centroid \: of\:the \: triangle\\=\left(\frac{11}{3},0\right)$

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