Question

if the coordinates of the vertex A of a square ABCD are (3,2)of the equation of the digonalBD is 3x-7y+6=0 find the equation of the diogonal ac ,also,find the coordinates of the centre of the square

Answer 1

Step-by-step explanation:

Slope of the diagonal BD = 3x - 7y + 6 = 0 is -(3) / (-7) = 3/7

Diagonals of a square are perpendicular to each other.

So, the slope of AC = -7/3 [Product of the slopes of the perpendicular lines is -1.]

AC passes through the vertex A(3, -2).

Equation of AC = (y - y1) = m(x - x1)

(y + 2) = -7/3(x - 3)

3y + 6 = -7x + 21

7x + 3y - 15 = 0

Point of intersection of the diagonals of the square is the midpoint of the diagonals. Solve the equations of the diagonals to find their midpoint.

Answer 2

Step-by-step explanation:

hope you understood.As diagonals AC and BD are perpendicular to each other