Math, asked by kavyaverma413, 9 months ago

If the coordinates of the vertices of a triangle are (6, 7).
(4. - 5) and (x, 2x) and its area is 3 sq. cm, find the value of
х.​

Answers

Answered by vaishnavipillai
1

Answer:

x=8

2x=16

Step-by-step explanation:

A(6,7)⇔(x₁,y₁)

B(4,-5)⇔(x₂,y₂)

C(x,2x)⇔(x₃,y₃)

Given: ar(ΔABC)=3 sq. units

ar(ΔABC)=¹/₂[x₁(y₂-y₃)+x₂(y₃-y₁)+x₃(y₁-y₂)]

3=¹/₂[6(-5-2x)+4(2x-7)+x(7+5)]

6=(-30-12x+8x-28+12x)

6=-58+8x

64=8x

x=⁶⁴/₈

x=8

∴2x=2×8=16

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