If the coordinates of the vertices of a triangle are (6, 7).
(4. - 5) and (x, 2x) and its area is 3 sq. cm, find the value of
х.
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Answer:
x=8
2x=16
Step-by-step explanation:
A(6,7)⇔(x₁,y₁)
B(4,-5)⇔(x₂,y₂)
C(x,2x)⇔(x₃,y₃)
Given: ar(ΔABC)=3 sq. units
ar(ΔABC)=¹/₂[x₁(y₂-y₃)+x₂(y₃-y₁)+x₃(y₁-y₂)]
3=¹/₂[6(-5-2x)+4(2x-7)+x(7+5)]
6=(-30-12x+8x-28+12x)
6=-58+8x
64=8x
x=⁶⁴/₈
x=8
∴2x=2×8=16
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