If the coordinates of two opposite vertices of a square are (6,-3) and (-2,3)
then the area of square
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Answer:
area = 50
Step-by-step explanation:
If a square has side length s, then by Pythagoras' Theorem, the length of the diagonal is
d = √(s²+s²) = √(2s²) = s√2.
So if we know the diagonal d, then we can get the side length:
s = d / √2.
As (6, -3) and (-2, 3) are opposite vertices of a square, the diagonal of the square is the distance between these points:
d = √( ( 6 - -2 )² + ( -3 - 3 )² ) = √( 8²+ 6² ) = √( 64 + 36 ) = √100 = 10
So the side length is
s = 10 / √2
and the area is then
area = s² = ( 10/√2 )² = 100 / 2 = 50
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