Question

If the copper loss of a transformer at 1/4 of its full load is 100w, then what is its full load copper loss? 257 views

Answer 1

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Answer 2

The full load Copper loss (w) is 1600w.

Given:-

Copper loss of transformer (w0)= 100w

Loss (l) = 1/4

Load (x) = 0.5

To Find:-

The full load Copper loss (w).

Solution:-

To find the full load Copper loss in the transformer, you can follow these simple steps which includes.

As,

Copper loss of transformer (w0)= 100w

Full load Copper loss (w) = ?

According to the formula,

Copper losses of transformer = loss * (load)² * full load of Copper loss

$wo = l \times {x}^{2} \times w$

$w = \frac{wo}{l \times {x}^{2} }$

$w = \frac{100}{ \frac{1}{4} \times {0.5}^{2} }$

$w = \frac{400}{ {(0.5)}^{2} }$

$w = 1600w$

Hence, The full load Copper loss (w) is 1600w.

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