if the cord joining the point (2, -1),(1,-2) substance a right angle at the centre of the circle then its centre and radius are
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Let A(2,-1)
B(1,-2)
centre O(x,y)
AO⊥BO,
Slope of AO* Slope if BO=-1
[(x-2)/(y+1)]*[(x-1)/(y+2)]=-1
[(x-2)*(x-1)]÷[(y+1)*(y+2)]=-1
(x²-3x+2)=-(y²+3y+2)
x² +y²-3x+3y+4=0
Also put
AO² =BO² And get x and y then radius also
B(1,-2)
centre O(x,y)
AO⊥BO,
Slope of AO* Slope if BO=-1
[(x-2)/(y+1)]*[(x-1)/(y+2)]=-1
[(x-2)*(x-1)]÷[(y+1)*(y+2)]=-1
(x²-3x+2)=-(y²+3y+2)
x² +y²-3x+3y+4=0
Also put
AO² =BO² And get x and y then radius also
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