if the corderanates of the vertex of two points b is o 3 and c 0 - 3 find cordenate a
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Answer:Let the third vertex of the equilateral ΔABC be A(x,y)
So by distance formula we have,
Distance between two points =
(x
2
−x
1
)
2
+(y
2
−y
1
)
2
∴BC=
(0−0)
2
+(3+3)
2
=
6
2
=
36
=6
∴AB=
(x−0)
2
+(y+3)
2
⇒AB
2
=x
2
+y
2
+2y=27 -----(1)
Now, AC=
(x−0)
2
+(y−3)
2
⇒AC
2
=x
2
+y
2
+9−6y=36
⇒27−2y−6y+9=36
⇒−8y=36−36
⇒y=0
∴x
2
=27
⇒x=
27
=
3×3×3
=+3
3
or−3
3
∴ Required points are A(3
3
,0) and A(−3
3
,0)
Step-by-step explanation:
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