If the correspondences ABC⇔BAC is similarity, then ΔABC is an isosceles triangle.State whether the given statement are true or false. Give reasons for your answer.
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the given statement is true .
If the correspondences ABC⇔BAC is similarity, then ΔABC is an isosceles triangle.
For ∆ABC, the correspondence ABC⇔BAC is a similarity.
∴ ∠A≅∠B
∴BC≅AC
Hence, two sides of ABC are congruent and therefore ∆ABC is an isosceles triangle.
If the correspondences ABC⇔BAC is similarity, then ΔABC is an isosceles triangle.
For ∆ABC, the correspondence ABC⇔BAC is a similarity.
∴ ∠A≅∠B
∴BC≅AC
Hence, two sides of ABC are congruent and therefore ∆ABC is an isosceles triangle.
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