if the corresponding sides of two similar triangles are 3 and 4 the areas of larger triangle is 48 CM square find the area of smallest square
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hey mate here is the answer
AB square/DE square = area of ∆ABC / area of ∆ DEF
This is formula Let area of smaller triangle is x
3 square /4 square = x / 48
9/16 = x/48
Cross multiplication
9*48 = 16x
Transposition
(9*48)/16 = x
(9*16*3)/16 = x (Because 48 = 16*3)
16 cancels 16
9*3 = x
27 = x
mark it as the brainliest answer
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