If the cosec of an angle complementary to A b 2/3√, find tan A.
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Explanation:
If the cosec of an angle complementary to A b 2/3√, find tan A.
2(cosec239°- tan251°) -2/3(sin90°) – tan256° y tan234° = y/3
⇒ 2(sec251° - tan251°) – 2/3 – y = y/3
⇒ 2(sec251° – sin251°/cos251°) – 2/3 = 4y/3
⇒ 2 – 2/3 = 4y/3
⇒ y = 4/3 × ¾ = 1
tan A= 1
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