If the cost of 20 pens is equal to the selling price of 15 pens. Find profit or loss percentage
Answers
Answer:
Answer:Let the C.P. be
Answer:Let the C.P. be ′
Answer:Let the C.P. be ′ x
Answer:Let the C.P. be ′ x ′
Answer:Let the C.P. be ′ x ′ & S.P. be
Answer:Let the C.P. be ′ x ′ & S.P. be ′
Answer:Let the C.P. be ′ x ′ & S.P. be ′ y
Answer:Let the C.P. be ′ x ′ & S.P. be ′ y ′
Answer:Let the C.P. be ′ x ′ & S.P. be ′ y ′
Answer:Let the C.P. be ′ x ′ & S.P. be ′ y ′ then 15x=20y ......(1)
Answer:Let the C.P. be ′ x ′ & S.P. be ′ y ′ then 15x=20y ......(1)As from (1) x>y⇒C.P.>S.P.
Answer:Let the C.P. be ′ x ′ & S.P. be ′ y ′ then 15x=20y ......(1)As from (1) x>y⇒C.P.>S.P.∴ loss
Answer:Let the C.P. be ′ x ′ & S.P. be ′ y ′ then 15x=20y ......(1)As from (1) x>y⇒C.P.>S.P.∴ loss⇒ Loss=
Answer:Let the C.P. be ′ x ′ & S.P. be ′ y ′ then 15x=20y ......(1)As from (1) x>y⇒C.P.>S.P.∴ loss⇒ Loss= C.P
Answer:Let the C.P. be ′ x ′ & S.P. be ′ y ′ then 15x=20y ......(1)As from (1) x>y⇒C.P.>S.P.∴ loss⇒ Loss= C.PC.P−S.P
Answer:Let the C.P. be ′ x ′ & S.P. be ′ y ′ then 15x=20y ......(1)As from (1) x>y⇒C.P.>S.P.∴ loss⇒ Loss= C.PC.P−S.P
Answer:Let the C.P. be ′ x ′ & S.P. be ′ y ′ then 15x=20y ......(1)As from (1) x>y⇒C.P.>S.P.∴ loss⇒ Loss= C.PC.P−S.P ×100=
Answer:Let the C.P. be ′ x ′ & S.P. be ′ y ′ then 15x=20y ......(1)As from (1) x>y⇒C.P.>S.P.∴ loss⇒ Loss= C.PC.P−S.P ×100= x
Answer:Let the C.P. be ′ x ′ & S.P. be ′ y ′ then 15x=20y ......(1)As from (1) x>y⇒C.P.>S.P.∴ loss⇒ Loss= C.PC.P−S.P ×100= xx−y
Answer:Let the C.P. be ′ x ′ & S.P. be ′ y ′ then 15x=20y ......(1)As from (1) x>y⇒C.P.>S.P.∴ loss⇒ Loss= C.PC.P−S.P ×100= xx−y
Answer:Let the C.P. be ′ x ′ & S.P. be ′ y ′ then 15x=20y ......(1)As from (1) x>y⇒C.P.>S.P.∴ loss⇒ Loss= C.PC.P−S.P ×100= xx−y ×100
Answer:Let the C.P. be ′ x ′ & S.P. be ′ y ′ then 15x=20y ......(1)As from (1) x>y⇒C.P.>S.P.∴ loss⇒ Loss= C.PC.P−S.P ×100= xx−y ×100⇒(1−
Answer:Let the C.P. be ′ x ′ & S.P. be ′ y ′ then 15x=20y ......(1)As from (1) x>y⇒C.P.>S.P.∴ loss⇒ Loss= C.PC.P−S.P ×100= xx−y ×100⇒(1− x
Answer:Let the C.P. be ′ x ′ & S.P. be ′ y ′ then 15x=20y ......(1)As from (1) x>y⇒C.P.>S.P.∴ loss⇒ Loss= C.PC.P−S.P ×100= xx−y ×100⇒(1− xy
Answer:Let the C.P. be ′ x ′ & S.P. be ′ y ′ then 15x=20y ......(1)As from (1) x>y⇒C.P.>S.P.∴ loss⇒ Loss= C.PC.P−S.P ×100= xx−y ×100⇒(1− xy
Answer:Let the C.P. be ′ x ′ & S.P. be ′ y ′ then 15x=20y ......(1)As from (1) x>y⇒C.P.>S.P.∴ loss⇒ Loss= C.PC.P−S.P ×100= xx−y ×100⇒(1− xy )100=(1−
Answer:Let the C.P. be ′ x ′ & S.P. be ′ y ′ then 15x=20y ......(1)As from (1) x>y⇒C.P.>S.P.∴ loss⇒ Loss= C.PC.P−S.P ×100= xx−y ×100⇒(1− xy )100=(1− 20
Answer:Let the C.P. be ′ x ′ & S.P. be ′ y ′ then 15x=20y ......(1)As from (1) x>y⇒C.P.>S.P.∴ loss⇒ Loss= C.PC.P−S.P ×100= xx−y ×100⇒(1− xy )100=(1− 2015
Answer:Let the C.P. be ′ x ′ & S.P. be ′ y ′ then 15x=20y ......(1)As from (1) x>y⇒C.P.>S.P.∴ loss⇒ Loss= C.PC.P−S.P ×100= xx−y ×100⇒(1− xy )100=(1− 2015
Answer:Let the C.P. be ′ x ′ & S.P. be ′ y ′ then 15x=20y ......(1)As from (1) x>y⇒C.P.>S.P.∴ loss⇒ Loss= C.PC.P−S.P ×100= xx−y ×100⇒(1− xy )100=(1− 2015 )100 .....(from (1))
Answer:Let the C.P. be ′ x ′ & S.P. be ′ y ′ then 15x=20y ......(1)As from (1) x>y⇒C.P.>S.P.∴ loss⇒ Loss= C.PC.P−S.P ×100= xx−y ×100⇒(1− xy )100=(1− 2015 )100 .....(from (1))=25% loss.
Let the cost of 1 pen be = ₹1
Selling price of 20 pens = ₹20
Cost price of 20 pens = Selling price of 15 pens = ₹15
Gain = SP - CP
Gain = ₹20 - ₹15 = ₹5
Gain% = Gain/CP x 100
Gain% = 5/15 x 100
Gain% = 33 isto 1/5