If the cost of 5 tables exceeds the cost of eight chairs by Rs.150. Write a linear equation in two variables. Also find the cost of one table if cost of one chair is Rs.240.
Answers
Answered by
282
Hey mate!
Here's your answer!!
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Let the cost of 1 table be x and the cost of 1 chair be y.
Cost of 5 tables = 5x
Cost of 8 chairs = 8y
8y + 150 = 5x
1 chair costs rs 240
(8 × 240) + 150 = 5x
1920 + 150 = 5x
5x = 2070
x = 2070/5
x = 414.
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#BE BRAINLY
Here's your answer!!
----------------------------
Let the cost of 1 table be x and the cost of 1 chair be y.
Cost of 5 tables = 5x
Cost of 8 chairs = 8y
8y + 150 = 5x
1 chair costs rs 240
(8 × 240) + 150 = 5x
1920 + 150 = 5x
5x = 2070
x = 2070/5
x = 414.
#BE BRAINLY
Answered by
119
Answer:
Let the cost of 1 table =Rs
Let the cost of 1 chair = Rs
cost of 5 tables = Rs 5
cost of 8 chairs = Rs 8
According to question,
5 − 8
= 150
Put = 240, we get
5 − 8 × 240 = 150
⇒5= 150 + 1920 = 2070
⇒ = 414
So, cost of 1 table = Rs 414
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