Question

If the cost of a toy car is given to be Rs (3y²-5y + 4) and number of toy cars bought is (2y²+y + 7)a) Find the total cost in terms of y b) Find the value when y-3.​​

Answer 1

Answer:

a)The total cost in terms of y=$6y^{4} -7y^{3} +24y^{2} -31y+28$

b) The total cost when y=3 is 448

Step-by-step explanation:

The given question can be solved with simple multiplication. The cost of one toy car is given as a quadratic equation of y and the number of toy cars bought is also given as a quadratic equation of y, inorder to find the total cost of the toy cars we need to multiply the number of toy cars to the cost of one toy car.

Cost of one toy car=$3y^{2} -5y+4$

Number of toy cars=$2y^{2} +y+7$

The total cost=$(3y^{2} -5y+4)(2y^{2} +y+7)=6y^{4} +3y^{3} +21y^{2} -10y^{3} -5y^{2} -35y+8y^{2} +4y+28=6y^{4} -7y^{3} +24y^{2} -31y+28$

The total cost if y=3,

$6y^{4} -7y^{3} +24y^{2} -31y+28\\=6.3^{4}-7.3^{3} +24.3^{2} -31.3+28\\=486-189+216-93+28\\=448$

The total cost of the toy cars is 448.