if the cost of an eraser is 80 paise and the cost of a pencil is 2rupees then find the ratio of their costs in simplest form.
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Answered by
2
Answer:
After the price reduction, 8 erasers are available for a rupee and that means initially 6 erasers were available for a rupee.
Let ‘x’ erasers could be bought for 1 Re initially.
This implies cost of one eraser is 1/x.
Now, the price has been reduced by 25%.
According to the question, ‘x+2’ erasers can be bought for 1 Re.
This implies now the new cost of one eraser is 1/(x+2).
As per the price reduction condition, 1/x has been reduced by 25% to change it into 1/(x+2)
therefore, [1/x - 25% of (1/x)] = 1/(x+2)
Solve this equation and the answer will be x = 6.
You can write this equation like this also.
75% of (1/x) = 1/(x + 2) [because the new cost is equal to 75% of the old cost]
I Hope It Will Help!
^_^
After the price reduction, 8 erasers are available for a rupee and that means initially 6 erasers were available for a rupee.
Let ‘x’ erasers could be bought for 1 Re initially.
This implies cost of one eraser is 1/x.
Now, the price has been reduced by 25%.
According to the question, ‘x+2’ erasers can be bought for 1 Re.
This implies now the new cost of one eraser is 1/(x+2).
As per the price reduction condition, 1/x has been reduced by 25% to change it into 1/(x+2)
therefore, [1/x - 25% of (1/x)] = 1/(x+2)
Solve this equation and the answer will be x = 6.
You can write this equation like this also.
75% of (1/x) = 1/(x + 2) [because the new cost is equal to 75% of the old cost]
I Hope It Will Help!
^_^
Answered by
7
Answer:
Step-by-step explanation:
Eraser 80 paise
Pencil 2rs = 200 paise
Eraser/pencil = 80/200
= 8/20
= 2/5
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=> 3x + 5y = 14
Since x & y are integers the only solution satisfying the above equation is,
x = 3 & y = 1
=> The cost of 10 pens & 12 pencils = 10x + 12y = 10*3 + 12*1 = 30 + 12 = 42